if the third term,sixth term and last term of a gp are 6, 48 and 3072. Find the first term and the number of terms in the G.P
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given :
ar²=6
ar'5=48.
ar'(n-1)= 3072 ,eq 1
term 6÷term3
r=3
a=3/2
after solving eq 1, we get
n=12
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