Math, asked by kulwantkaur5291, 8 months ago

If the three numbers in the ratio 3:2:5 be such that the sum of the squares is equal to 1862 then which number is the middle one.

A) 16 B) 14 C) 13 D) 15

Answers

Answered by bktbunu
0

Answer:

B) 14

Step-by-step explanation:

numbers in ratio 3:2:5 = 3x:2x:5x

given (3x)^2 + (2x)^2 + (5x)^2 = 1862

=> 9x^2 + 4x^2 + 25x^2 = 1862

=> 38x^2 = 1862

=> x^2 = 1862/38 = 49

=> x = 7

2x= 14 <--- middle one

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