Question

If the three positive numbers are k+4, 4k-2 and 7k+1 are in G.P, find the numbers.​

Answer 1

Answer:

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Step-by-step explanation:

(k+1/k-3) = (4k-2)/(k+1)

=> (k+1)^2 = (4k-2)(k-3)

=> K^2+2k+1= 4k^2-14k+6

=> 3k^2–16k+5=0

=> 3k^2 -15k -k+5=0

=> (k-5)(3k-1)=0 ,

k-5 =0 or 3k-1=0

k =5 or 1/3

When k=5 , numbers are 5–3,5+1,4*5–2