if the three terms 2k+3, 3k+1and 5k+3are in arithmetic progress, then what will be the value of k
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Answer:
2k+1=a
3k+3=b
5k-1=c
To form an AP
a+c=2b
2k+1+5k-1=2(3k+3)
7k=6k+6
So,k=6
So,l hope it's help you
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