Question

if the time period of revolution of the satellite is 6 hours and the radius of the orbit is 12000km find its revolution speed​

Answer 1

Answer:example

Explanation:3. The mass of planet Jupiter is 1.9 × 1027 kg and that of the Sun is 1.99 × 1030

kg. The average distance of the Sun from Jupiter is 7.8 × 1011 m. Calculate

the gravitational force exerted by the Sun on Jupiter and orbital speed of

Jupiter assuming the orbit of Jupiter is circular.

Sol. Here, m1

= 1.9 × 1027 kg, m2

= 1.99 × 1030 kg,

r = 7.8 × 1011 m, G = 6.67 × 10–11 N m2

/kg2

F Gm m

r = = × × × × ×

×

−

1 2

2

11 27 30

11 2

6 67 10 1 9 10 1 99 10

7 8 10

. . .

( . ) = 4.15 × 1023 N.

The centripetal force required by the Jupiter to move in the circular orbit

around the, Sun is provided by the gravitational force between them.

⇒ F m v

r

v

Fr

m

= ⇒ = 1

2

1

⇒ v =

4 15 10 7 8 10

1 9 10

23 11

27

. .

.

× × ×

×

= 1.3 × 104

m/s.