Question

If the toot of2 x^-6x + k=0 are real and equal find k?​

Answer 1

The value of k = 9/2 = 4.5

Step-by-step explanation:

If the roots of a quadratic equation are real and equal then

Discriminant(b^2 - 4ac) of  Quadratic equation is zero.

It is given a quadratic equation

2x2- 6x + k = 0,

the roots of  are real and equal.

Therefore Discriminant of  Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of  2x2- 6x + k = 0,

a = 2

b = -6

c = k

To find the value of k

b^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36

k = 36/8 = 9 /2 = 4.5

Answer 2

ANSWER❣❣⭐⭐

For equal and real roots

b^2-4ac=0

So quadratic equation is

2x^2-6X+k=0

Here, a=2

b=-6

c=k

(-6)^2-4(2)k=0

36-8k=0

36=8k

k=36/8=18/4

k=9/2

HOPE IT HELPS YOU✔✔✨✨✌✌