if the total energy of an electron -1.51 eV in hydrogen atom then find out K.E,P.E , orbit radius and velocity of the electron in that orbit.
Answers
Answered by
0
potential energy equal to 2times T.E & K.E=-T.E
thus P.E = -3.02 & K.E= +1.51 eV
it lies in 3rd orbit from the formula E=-13.6/n^2 ,
orbit radius = 0.529(n^2) A°
= 0.529(9)
= 4.761 A°
Velocity in the 3rd orbit is Vn = {c/137}z/n
V3 = {c/137}1/3
= c/411 m/s , where c is the velocity light in vaccum
Similar questions