Physics, asked by disha2106, 11 months ago

If the total energy of an electron in a hydrogen like atom in an excited state is –3.4 eV then the de-Broglie wavelength of the electron is

A)
6.6×10^−10

B)
3×10^−10

C)
5×10^−9

D)
9.3×10^−12

Answers

Answered by Anonymous
0

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wavelength of the electron is; (a)6.6×10−10


disha2106: Pls explain how you did it
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