if the triangle ABC, DE parallel BC and DE:BC=4:5, find the area of triangle ADE to area of trapezium BCED.
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DE/BC =4:5
area of triangle ADE /area of triangle ABC=(DE)^2/(BC)^2=16/25
=area of triangle ADE/area of trapezium DBCE=16/9
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area of triangle ADE /area of triangle ABC=(DE)^2/(BC)^2=16/25
=area of triangle ADE/area of trapezium DBCE=16/9
please follow me.......☺☺
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