If the two parents are with the genotypes RrYyttVv and RryyTtVv, when they are allowed to fertilize how many different types of phenotypes and genotypes are their in offspring?
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Answer: no. of phenotypes=8
no. of genotypes= 27
Explanation: no. of phenotypes= 2^n, n=no. of heterozygous pair in any one parent.
no. of genotypes=3^n, n-same as given above.
In RrYyttVv &RryyTtVv there are 3 heterozygous pair
i.e, Rr, Yy, Vv & Rr, Tt, Vv
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