Math, asked by echlipse82, 1 year ago

if the two roots of the equation (a-b)x2 + (b-c) x + (c-a) =0 are equal. prove that 2a=b+c

Answers

Answered by Anonymous
3

Answer:

The two roots are equal

=> discriminant = 0

=> (b-c)² - 4(a-b)(c-a) = 0

=> b² - 2bc + c² - 4ac + 4a² + 4bc - 4ab = 0

=> b² + 2bc + c² - 4ac + 4a² - 4ab = 0

=> (b+c)² - 4a(b+c) + 4a² = 0

=> ( (b+c) - 2a )² = 0

=> b+c - 2a = 0

=> 2a = b+c


Anonymous: Hello. I hope this helps you. Plz mark it brainliest. Have a good day!
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