Question

solve this with one variable.pls

Answer 1

Answer:

Step-by-step explanation:

Let units digit of the no. be= x

Therefore tens digit= 14-x

Original no.= 10(14-x) + x

When 36 is added

Units digit= 14-x

Ones digit= x

New no.= 10x + (14-x)

Equation:

10(14-x) + x +36= 10x + (14-x)

=>140 -10x +x +36= 10x + 14 -x

=>-9x + 176= 9x+ 14

=>-9x-9x= 14-176

=>-18x= -162

=>x= -162/-18

=>x= 9

Original no.= 10(14-9) + 9

=>10*5 + 9

=>50 + 9

=>59

Answer 2

Let the Digit in the units place of the Two Digit number be : A

Given : The Sum of the Digits of Two Digit number is 14

It means : The Digit in the Ten's place will be : 14 - A

★  The Two Digit Number can be written as : 10(14 - A) + A

Given : If 36 is added to the number, the Digits get interchanged

$\mathsf{\implies 10(14 - A) + A + 36 = 10(A) + (14 - A)}$

$\mathsf{\implies 140 - 10A + A + 36 = 10A + 14 - A}$

$\mathsf{\implies 176 - 9A = 9A + 14}$

$\mathsf{\implies 9A + 9A = 176 - 14}$

$\mathsf{\implies 18A = 162}$

$\mathsf{\implies A = 9}$

$\mathsf{\implies Ten's\;Place\;Digit = (14 - 9) = 5}$

Answer : The Two Digit Number is 59