Question

If the two roots of the quadratic equation ax2+ bx+c=0 are reciprocal to each other then the value of c will be

Answer 1

Step-by-step explanation:

HEY MATE YOUR ANSWER IS HERE ^_^

it means that

{(-b-√[b^2-4ac])/2a} × {2a /(-b+√[b^2-4ac]) = 1

(-b-√[b^2-4ac])/(-b+√[b^2-4ac]) = 1

by rationalisation

-{(b+√[b^2-4ac])}^2/(b^2-b^2+4ac) = 1

{-2b^2+4ac-2b√[b^2-4ac] } / 4ac = 1

2b^2 = - 2b√[b^2-4ac]

b^2 = b^2 - 4ac

4ac = 0

c = 0

PLEASE MAKE ME A BRAINLIST ANSWER FOR THE QUESTION