Question

If the uncertainty in the velocity of electron is 0.06 m/s , what is the uncertainty in the position of electron​

Answer 1

Answer:

9.76*10∧-4m

Step-by.

Heisenbergs incertainity principle equation = ΔxΔp=h/4π

=ΔxmΔv=h/4π

=Δx=h/4π*m*Δv

m=9*10^-31

h=6.626*10^.34

π=3.14

Δv=0.06

∴Δx=9.769*10^-4m