If the unit of length is tripled, the numerial value of area of square will be
(A) one ninth (B) one sixth
(C) nine times (D) remains same
Answers
Answered by
2
!! Hey Mate !!
Your answer is --
Let, the length of square be l
So, area of square is
S1 = l × l = l^2 unit
Since, length of square become triple
such that length = 3l
So, area of S2 = 3l × 3l = 9l^2
=> S2 = 9S1.
Therefore, the value of area of new square is 9 time the first one .
Hence, option (C) is right
【 Hope it helps you 】
Your answer is --
Let, the length of square be l
So, area of square is
S1 = l × l = l^2 unit
Since, length of square become triple
such that length = 3l
So, area of S2 = 3l × 3l = 9l^2
=> S2 = 9S1.
Therefore, the value of area of new square is 9 time the first one .
Hence, option (C) is right
【 Hope it helps you 】
purvish118:
Thanks
Similar questions