Chemistry, asked by sakshipatil42, 9 months ago

If the v is 30R 1/2 at 27°C then calculate the molar
mass of gas in kilogram.
[DUCMET]​

Answers

Answered by bhagyashreechowdhury
7

If the v is 30√R at 27°C then the molar mass of gas is 0.001 kg.

Explanation:

It is given that,

The root mean square velocity of the gas, v = 30√R

Temperature, T = 27°C = 27 + 273 K = 300 K

We know the formula for the root mean square velocity of the gas is given by,

Vrms = \sqrt{\frac{3RT}{M}}

Where,

R = ideal gas constant

T = temperature

M = molar mass of the gas

Substituting the given values in the formula, we get

30√R = \sqrt{\frac{3*R* 300}{M}}

Taking square on both sides

⇒ 30² * R = \frac{3*R*300}{M}

⇒ M = \frac{3*300}{30 * 30}

⇒ M = 1 g

⇒ M = 1/1000 kg

M = 0.001 kg

Thus, the molar mass of the gas in kilograms is 0.001.

-----------------------------------------------------------------------------------------------

Also View:

If the average velocity of the molecules of a gas is doubled, then what will happen to the root mean square velocity?

https://brainly.in/question/11896990

The average velocity of gas molecules is 400 m/sec. Calculate its rms velocity at the same temperature.

https://brainly.in/question/8159531

Answered by likhitha2005
0

Answer:

Ans =0.001kg

hopes it helps you

Similar questions