Question

If the value of 19! is 1216 T510040 M832 H00, where, T, M & H are single digit integers, then the value of T + M + H is​

Answer 1

Answer:

Step-by-step explanation:

If you multiply 19 x 18 x 17---x 4 x 3 x 2 x 1

= 121645100408832000

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Answer 2

$T+M+H=12$

Step-by-step explanation:

• To solve the question, first, we need to find the value $19!$
• For this, we need to multiply all the numbers from 19 to 1.

• So, we can write,

$19! =19\times18\times17\times16\times15\times14\times13\times12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1$

$19!=121645100408832000$

• Comparing the result with the given value:
• 1216 4510040 8832 000
• 1216 T510040 M832 H00

Thus, $T = 4, M =8,$ and $H =0$

• Then, the sum would be

$T+M+H = 4+8+0 =12$