Question

If the value of the solubility product of ba(oh)2 is 3.2*10to the power -5 then the ph of saturated solution of ba(oh)2 will be ?

Answer 1

Hi, please consider the answer given below;

In this case, you need to get the concentration of the OH- ions from the solubility product.

The equation is; Ba(OH)2 --------> Ba²⁺ + 2OH⁻

So the expression for the solubility product is given as;

ksp= [Ba²⁺] [OH⁻]²

So we can as well write it as ksp= S³ Where S is the solubility or concentration

S= ∛3.2 x 10⁻⁵

S = 0.03

But the concentration of the OH- ions is 2 x 0.03 =0.063 M

Then pOH= -log 0.063

         pOH = 1.2

            pH= 12.8