Question

If the value of x and y are 8x + i(2x-y) = 3 - 8i, and x, y ∈ R, then the value of x and y are​

Answer 1

Answer:

x = 3/8 and y = 35/4

Step-by-step explanation:

by equating the real part and Imaginary part separately

Answer 2

Answer:

Required values of x and y are $\frac{3}{8}$and $\frac{35}{4}$respectively.

Step-by-step explanation:

Given,

$8x + i(2x-y) = 3 - 8i$

We are comparing both side of the equation and get,

$8x = 3....(1)$

and $2x - y = - 8......(2)$

From equation (1),

$8x = 3$

$x = \frac{3}{8}$

Value of x is $\frac{3}{8}$

We are putting value of x in the equation (2),

$2 \times \frac{3}{8} - y = - 8$

$\frac{3}{4} - y = - 8$

Now we are separating variable and constant part,

$y = \frac{3}{4} + 8$

$y = \frac{35}{4}$

So,value of y is $\frac{35}{4}$