Math, asked by modiabhishek999, 9 months ago

The digit in the tens place of a two-digit no. Is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number. check your solution.

Answers

Answered by Anonymous
4

Answer:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

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