Question

if the value of x2 + Y2 square= 67 and xy = 9 then find the value of x- y​

Answer 1

Answer:

$(x - y)^{2} = {x}^{2} + {y}^{2} - 2xy \\ = 67 - 2 \times 9 \\ = 67 - 18 \\ = (x - y)^{2} = 49 \\ x - y = \pm\sqrt{49} \\ x - y = \pm \: 7$