Question

If the values a a,-11 8{5,b} 2,15 and d 1,1 are the vertices of a pallelogram abcd find the value of a and b

Answer 1

Answer:

Correct question:–

• If the values of A(a,-11),B(5,b),C(2,15) and D(1,1) are the vertices of a parallelogram ABCD.Then find the value of a and b?

Answer:–

As we know that,

In a parallelogram,

Coordinates of AC=Coordinates of BD

$( \frac{a + 2}{2}, \frac{ - 11 + 15}{2}) = ( \frac{5 + 1}{2} ,\frac{b + 1}{2} )$

$\frac{a + 2}{2} = \frac{6}{2}$

And, $\frac{4}{2} = \frac{b + 1}{2}$

$a + 2 = 6 \\ a = 4$

$b + 1 = 4 \\ b = 3$

$<marquee > the value of a and b is 4 and 3 respectively.<marquee>$

Answer 2

Answer:

Let A(a, -11), B(5, b), C(2, 15) and D(1,1) be the given points. We know that diagonals of parallelogram bisect each other. Therefore, Coordinates of mid-point of AC = Coordinates of mid-point of BD Read more on Sarthaks.com - https://www.sarthaks.com/103908/if-the-points-11-2-15-and-d-1-1-are-the-vertices-of-a-parallelogram-abcd-find-the-values-of-a-and

Step-by-step explanation:

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