Chemistry, asked by saabujoseph, 1 year ago

If the vapour density of an oxide of divalent metal is 20 then the equivalent weight of metal is

Answers

Answered by meenakshi997sa

molecular mass = 2 ×vapour density

=> molecular mass= 2*20 = 40

equivalent weight of metal = molecular mass/valency

=> equivalent mass= 40/2 = 20

hope it helps you.....
:)...

saigonecrazy: no yaar the answer is 12, u calculated molecular mass not equivalent weight

saigonecrazy: both are diff

meenakshi997sa: i calculated equivalent mass only...!!

meenakshi997sa: how did u get 12u??? explain plz

meenakshi997sa: ohhhhh....!!!!! yeah... ri8!!!!!

meenakshi997sa: sorry 4 the mistake

meenakshi997sa: Emo= Em+EO. hence Em= Emo-Eo= 20-8=12

meenakshi997sa: i calculated equivalent mass of metal oxide and not molecular mass of metal oxide saigoncrazy!!!..... :).... hope u understood...

Answered by kobenhavn

The equivalent weight of metal is 12.

Explanation:

Molar mass is twice of that of vapor density.

Molar mass = 2 × vapor density

Given: Vapor density of oxide of divalent metal = 20

Molar mass of oxide of divalent metal = 2 × vapor density = $2\times 20=40$

Equivalent weight is calculated by dividing the molecular weight by n factor.

${\text{Equivalent weight of oxide of divalent metal}}=\frac{\text{Molecular weight of oxide of divalent metal}}{n}$

where n = valency, for elements ( here n =2 as metal is divalent )

${\text{Equivalent weight of oxide of divalent metal}}=\frac{40}{2}=20$

Thus the equivalent weight of metal is = equivalent weight of oxide of divalent metal - equivalent weight of oxygen = 20- 8 = 12

Thus the equivalent weight of metal is 12.

Learn more about equivalent mass

https://brainly.in/question/8796857

https://brainly.in/question/3603787

Previous Question

Next Question