if the vectors 2i+3j-6k and 4i-mj - 12k are parallel, find m
Answers
Well that's quite simple if you know the dot product and cross product concept in vectors.When two vectors are perpendicular to each other then their dot product is always equal to 0. As per the vectors rules for dot product:
1. i.i=1
2. j.j=1
3. k.k=1
4. i.j=0
5. j.k=0
6. i.k=0
So if you remember these rules this question is quite easy to solve.What you have to do is multiply the two given vectors according to the dot products rules.
So we have, A.B=0
(2i+2j+3k).(3i+6k+nk)=0
2i.3i + 2j.0j + 3k.(6+n)k =0
6+3(6+n)=0
6+n=-2
n=-8
Therefore the value of n is -8 for the two vectors A and B to be perpendicular.
Hope it helps! :)
Answer:
m=6
Step-by-step explanation:
Vectors are geometrical entities which have significance and route. A vector may be represented through a line with an arrow pointing closer to its route and its period represents the significance of the vector. Therefore, vectors are represented through arrows, they have got preliminary factors and terminal factors.
vector, in mathematics, a amount that has each significance and route however now no longer position. Examples of such portions are speed and acceleration.
The vectors are parallel if the drs are proportional
Vector formulation offer a listing of formulation, beneficial for carrying out severa mathematics operations at the identical vector, and among vectors. Vectors have each a scalar and a vector aspect and those vector formulation assist in appearing the severa operations on vectors in a scientific and smooth manner.
2/4= -3/-m -6/-12
3/m=1/2
m=6
some related links
https://brainly.in/textbook-solutions/q-let-c-vector-perpendicular-vectors-i-j
https://brainly.in/textbook-solutions/q-let-vectors-b-c-2-b-4
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