Question

if the velocit of aparticle is given by v=(180-16x)^1/2 m/s then its acceleration will be

Answer 1

v = √(180 - 16x)
v² = 180 - 16x
Differentiate with dt
2vdv/dt = -16 dx/dt
2va = -16v
a = -8m/s²

Answer 2

If the velocity of a particle is given by v= (180-16x) ^1/2 m/s then its acceleration will be V = √ (180 - 16x), v² = 180 - 16x,

Differentiate with dt ,

2vdv/dt = -16 dx/dt,

2va = -16v,

a = -8m/s².

form this your answer will be a = -8m/s².