Question

If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1s and 2s is : (a) $\frac{3}{2}A + 4B$(b) 3A + 7B(c) $\frac{3}{2}A + \frac{7}{3}B$(d) $\frac{A}{2} + \frac{B}{3}$

Answer 1

hey dear

ur answer is ^_^

option no b

thanka

Answer 2

Answer:

option b is your answer.

Explanation:

hope it helps you.....