If the velocity of a particle v as a function of
time t is given by the equation, V = a(1 - e-bt),
where a and b are constants, then the
dimension of the quantity a2b3 will be
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Answer:
According to the principle of dimensional homogenity
Dimension of v = dimension of at = dimension of
t+c
b
Dimension of a =
[t]
[v]
=
T
LT
−2
=[LT
−2
]
Dimension of b = [v][t]=[LT
−1
T]=[L]
Dimension of c = [t]=[T]
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