Physics, asked by ParthThakre9965, 1 year ago

if the velocity of a particle v=bs^2, where b is constant and s is displacement. the acceleration of the particle's function of s is.

Answers

Answered by yuvrajkj
1
v = bs^2
=> acceleration = dv/dt or d^2s/dt^2
=> 2bs

ParthThakre9965: but the answer given is 2b^s^3
yuvrajkj: then plz consult your teacher
yuvrajkj: which book is that?
ParthThakre9965: its in a paper
yuvrajkj: ok
ParthThakre9965: pls see to it
ParthThakre9965: acceleration is v(dv/ds) and it is asked as a function of s
ParthThakre9965: 2b^s^3
ParthThakre9965: is correct
ParthThakre9965: thanks btw
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