if the velocity of a particle v=bs^2, where b is constant and s is displacement. the acceleration of the particle's function of s is.
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v = bs^2
=> acceleration = dv/dt or d^2s/dt^2
=> 2bs
=> acceleration = dv/dt or d^2s/dt^2
=> 2bs
ParthThakre9965:
but the answer given is 2b^s^3
then plz consult your teacher
which book is that?
its in a paper
ok
pls see to it
acceleration is v(dv/ds) and it is asked as a function of s
2b^s^3
is correct
thanks btw
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