If the velocity of an object is doubled, what will be the change in its kinetic energy? Please answer correctly, correct answer will be chosen as brainliest and unwanted answers will be reported.
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Answer:
K.E is 4 times when velocity is doubled
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Let the mass of the object be = (m)
Assume it's initial velocity as = (v)
So, Initial KE = ½ mv^2
Now, final velocity = (2v)
∴ Final KE = ½ (m)(2 v)²
⇒ Final KE = 2 mv²
So, ∆KE = Final KE - Initial KE
⇒ ∆KE = 2 mv² - ½ mv²
⇒ ∆KE = 3/2 mv².
∴ ∆KE is 3/2 mv².
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