if the velocity of bullet is 20m/s and the and it goes 5cm under the wall what is the deceleration
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Deceleration = -(v² - u²) / (2S)
= [-(0² - 20²) / (2 × 0.05)] m/s²
= 4000 m/s²
= 4 km/s²
∴ Deceleration or bullet is 4 km/s²
= [-(0² - 20²) / (2 × 0.05)] m/s²
= 4000 m/s²
= 4 km/s²
∴ Deceleration or bullet is 4 km/s²
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