Physics, asked by Abhayrajsharma7036, 11 months ago

If the velocity of electron in bohr first orbit is 2.19*10^6 m/s, calculatr de broglie associated with iit

Answers

Answered by adnanjelaniadj

0

your answer is 332pm

Answered by anasuyab46

1

Answer:

332 pm

Explanation:

From de Brogle equation----

λ=h/mv=6.626 × 10^-34 Js/9.1 × 10^-31 × 2.19 × 10^6= 6.626 × 10^-34 Js/19.929 x 10^-25= 0.332 x 10^-9 m=3.32 x 10^-10 m=332 pm

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