If the velocity of electron in bohr first orbit is 2.19*10^6 m/s, calculatr de broglie associated with iit
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your answer is 332pm
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Answer:
332 pm
Explanation:
From de Brogle equation----
λ=h/mv=6.626 × 10^-34 Js/9.1 × 10^-31 × 2.19 × 10^6= 6.626 × 10^-34 Js/19.929 x 10^-25= 0.332 x 10^-9 m=3.32 x 10^-10 m=332 pm
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