If the velocity of hydrogen molecule is 5×10^4 cm/sec then its de broglie wavelength is
Answers
velocity of hydrogen molecule, v = 5 × 10⁴ cm/s or 5 × 10² m/s
mass of one mole of hydrogen molecules = 2g
so, mass of one hydrogen molecule , m = 2g/Avogadro's number
=2/6.023 × 10²³ g
= 2 × 0.166 × 10^-23 g
= 0.332 × 10^-26 kg
= 3.32 × 10^-27 Kg
using De-broglie's wavelength equation,
wavelength = h/mv
= 6.63 × 10^-34Js/(3.32 × 10^-27 kg × 5 × 10² m/s)
≈ 0.4 × 10^-9 m
≈ 4 A°
hence, answer should be 4A°
Answer: 4A°
Explanation:
velocity of hydrogen molecule, v = 5 × 10⁴ cm/s or 5 × 10² m/s
mass of one mole of hydrogen molecules = 2g
so, mass of one hydrogen molecule , m = 2g/Avogadro's number
=2/6.023 × 10²³ g
= 2 × 0.166 × 10^-23 g
= 0.332 × 10^-26 kg
= 3.32 × 10^-27 Kg
using De-broglie's wavelength equation,
wavelength = h/mv
= 6.63 × 10^-34Js/(3.32 × 10^-27 kg × 5 × 10² m/s)
≈ 0.4 × 10^-9 m
≈ 4A°