Question

If the velocity of sound in air is 330 m/s to express the audible range of frequency in terms of frequency

Answer 1

Answer:

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Explanation:

Audible range of frequencies are V1 = 20 Hz, V2 = 20000 Hz and

the velocity, v = 330 ms-1

So, time period will become,

T1 =

1

V

1

=

1

20

= 5 x 10-2 s and time period will become

T2 =

1

V

2

=

1

20000

= 5 x 10-5 s

Thus, the audible range in terms of time period is from 5 x 10-2 s to 5 x 10-5 s.