Question

if the velocity position relation of a particle moving in a straight line is given as v²=a- bx² then acceleration of particle proportional to?​

Answer 1

Hey Dear,

◆ Answer -

a ∝ x

● Explanation -

Velocity-displacement of a particle is related as -

v²= a - bx²

Differentiating w.r.t. x,

2v × dv/dx = 0 - 2bx

2 × dx/dt × dv/dx = -2bx

dv/dt = -bx

a = -bx

a ∝ x

Therefore, acceleration of particle proportional to displacement of the particle.

Thanks for asking. Hope this was useful..