Question

If the velocity 'V' related to time as:
V = at^3 + bt^2
Find the dimention of a and b​

Answer 1

Answer:

dimension of a

at^3 =V

a= V/t^3

a= LT^-1/T^3

a= LT^-4

dimension of b

bt^2=V

b= V/t^2

b= LT^-3

Answer 2

Answer:

dimension of a

at^3 =V

a= V/t^3

a= LT^-1/T^3

a= LT^-4

dimension of b

bt^2=V

b= V/t^2

b= LT^-3

Thanks..