If the Vertical angle of an isosceles triangle is 100 degrees find the measure of its base angles.
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Answered by
3
Let triangle be ABC, Such that AB=AC
so, ∠B = ∠C [∠s opp to eq. sides are equal]
and , ∠A = 100°
so, ∠A + ∠B +∠C = 180°
so, 2∠B = 80°
∠B = 40°
So base angle is 40°
so, ∠B = ∠C [∠s opp to eq. sides are equal]
and , ∠A = 100°
so, ∠A + ∠B +∠C = 180°
so, 2∠B = 80°
∠B = 40°
So base angle is 40°
Answered by
2
Hey !
_____________________________________________
◆ Given that triangle is 100 ° ◆
if it is isocles triangle then base if triangle will be
( 180 - 100 ° )
= 80 °
=> 80 / 2
=> 40°
_____________________________________________
◆ Given that triangle is 100 ° ◆
if it is isocles triangle then base if triangle will be
( 180 - 100 ° )
= 80 °
=> 80 / 2
=> 40°
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