If the vertices of a triangle are (1, 4, 2), (-2, 1, 2), (2, -3, 4) then the angles are
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Answer:
→
AB
=−3
i
^
−3
j
^
+0
k
^
AC
=
i
^
−
j
^
−6
k
^
BC
=4
i
^
+2
j
^
−6
k
^
⇒cosA=
∣
∣
∣
∣
∣
∣
AB
∣∣
AC
∣
AB
.
AC
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
9+9
.
1+1+12
−3+3
∣
∣
∣
∣
∣
=0⇒A=90
o
⇒cosB=
∣
∣
∣
∣
∣
∣
AB
∣∣
BC
∣
AB
.
BC
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
18
×
16+4+36
−12−6
∣
∣
∣
∣
∣
=
18×56
−18
cosB=
56
18
=
28
9
→B=cos
−1
28
9
and C=90
o
−cos
−1
28
9
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