Question

if the volume of a cube is 729 cm³ , then what is the length of its diagonals?​

Answer 1

Answer:

Let, the side of the cube is a

ATQ

$a {3} \: = \: 729$

$= > \: a = \: \sqrt[3]729{}$

$= > \: a \: = \: 9$

$\: length \: of \: its \: diagonals = \: \sqrt{3 \: } \: \times a$

$= \: \sqrt{3} \: \times \: 9$

$= \: 9 \sqrt{3}$

Answer 2

Answer:

The answer is ≈ 15.588

Explanation:

the explanation is in the picture.