Question

If the volume of a cube is Vcm^3,its surface area is Scm^2 and length of a diagonal is d cm,prove that V= [1/(6√3)] S∙d

Answer 1

Solve the RHS first...
$1 \div (6 \sqrt{3} ) \times s \times d$
s is 6a^2
d is a√3
so it becomes a^3 which is the volume of cube....

Any query is welcome

Answer 2

Answer:

no need to mark be as brainliest just thank me