if the volume of a cubiod is 3x2 -27 then the possible dimensions
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Let the breadth of the box be X m.
Then, its height = 10 times as breadth = 10X m.
And, its length = 32 times as height = 32(10X)= 320X m.
Given that, its volume = 25.6 m3
We know that, the volume of the box = height x length x breadth m3.
i.e., X x 10X x 320X m3 = 25.6 m3
3200(X3) = 25.6
X3 = 25.6/3200 = 256/32000 = 1/125
X = (1/125)(1/3) = 1/5
Therefore, X = 1/5 m = 1/5 x 100 cm = 20 cm.
Hence the answer is none of these.
Question 2
Let the breadth of the box be X m.
Then, its height = 10 times as breadth = 10X m.
And, its length = 32 times as height = 32(10X)= 320X m.
Given that, its volume = 25.6 m3
We know that, the volume of the box = height x length x breadth m3.
i.e., X x 10X x 320X m3 = 25.6 m3
3200(X3) = 25.6
X3 = 25.6/3200 = 256/32000 = 1/125
X = (1/125)(1/3) = 1/5
Therefore, X = 1/5 m = 1/5 x 100 cm = 20 cm.
Hence the answer is none of these.
Question 2
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