if the volume of cube is 729 cm3 what is the total length of its edges what is the total surface area
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Answered by
9
Let x = side of a cube Volume = 729 cm³
Volume = (x) (x) (x) or V = x³
729 = x³
∛729 = ∛x
∛729 = x
9 = x Side a cube is 9 cm
To find surface area of a cube:
Surface Area = 6x²
Surface area = 6 (9)²
= 6 (81)
= 486 cm³
Answered by
9
let a be the edge of cube .
volume of the cube = 729 cm^3
Find the edge:
--------------------
since, we know that
volume of cube = ( edge)^3 = a^3
a^3 = 729 => a = cube√729
a = 9cm
edge of cube = 9cm
Find the total length:
----------------------------
total length of edges = perimeter of cube
= 12a = 12 × 9 = 108 cm
Find the area:
-------------------
are of the cube = 6 ( edge )^2 = 6a^2
area of the cube = 6 (9)^2
6 × 81 = 486 cm^2
therefore,
total surface area of the cube
= 486cm^2
total length of edges = 108 cm
Answer: p = 108cm, area = 486cm^2
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volume of the cube = 729 cm^3
Find the edge:
--------------------
since, we know that
volume of cube = ( edge)^3 = a^3
a^3 = 729 => a = cube√729
a = 9cm
edge of cube = 9cm
Find the total length:
----------------------------
total length of edges = perimeter of cube
= 12a = 12 × 9 = 108 cm
Find the area:
-------------------
are of the cube = 6 ( edge )^2 = 6a^2
area of the cube = 6 (9)^2
6 × 81 = 486 cm^2
therefore,
total surface area of the cube
= 486cm^2
total length of edges = 108 cm
Answer: p = 108cm, area = 486cm^2
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Inflameroftheancient:
Perfect!
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