Question

.If the water absorbed by soaked raisins is 50% then the weight of raisins before soaking inwater W1 and the weight of raisins after soaking in water W2 might have been
a) W1 = 30g and W2 = 50 g
b) W1 = 50g and W2 = 100 g
c) W1 = 5 g and W2 = 25 g
d) W1 = 20g and W2 = 30 g​

Answer 1

Given :- v² + 2v + ?

To Find :- fill in the blank with the number to make an expression a perfect square: v² + 2v + ?

Solution :-

We know that, a² + 2ab + b² = (a + b)²

v² + 2v + ? = v² + 2v(1) + (1)²

= v² + 2v + 1 = (v + 1)²

Hence, the blank with the number to make an expression a perfect square: v² + 2v + ? is 1.

Hence, the final answer is 1.

Answer 2

The soaking in water  $W_{1}$ and the weight of raisins after soaking in water $W_{2}$  might the $W_{1}=30gandW_{2}=50g$.

Explanation:

$=(w2-w1)*100$

$=(30-20/20)*100$

$=10/20*100$

$=50%$%.

$=(w2-w1/w1)*100$

$=(50-30/30)*100$

$=20/30*100$

$=66.6$%.