If the water of mass 60g and temperature
60°C is mixed with water of mass 60 g
and temperature 40°C, what will be the
maximum temperature of the mixture??
Plz answer it's urgent tomorrow is my paper...........
Answers
Answered by
1
Answer:
20 DEGREE CENTIGRATE IS THE ANSWER
Answered by
12
Answer:
M1=60g,T1=60°c,M2=60g,T2=40°c,T=?
M1(T1-T)=m2c(T-T2)
m1T1-m1T=m2T-m2T2
m1T1+m2T2=(m1+m2)T
maximum temperature of the mixture,
T=m1T1+m2T2/M1+M2
60g×60°c+60g×40°c/60g+60g
60×60/120+60×40/120
30+20
50
therefore,the maximum temperature of the mixture is 50
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