Math, asked by gowthamcrontecpausiq, 1 year ago

Answer this question​

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Answered by nikki200414
1

at first find the area of whole figure then find the unshaded region

now area of the shaded region -the area of the shaded region =ur answer

I hope this will help you

Answered by mee30
4

Answer:

Step-by-step explanation:

CYLINDER

GIVEN:

Height of cylinder (h) = 14cm

Radius of cylinder (r) = 7/2

CSA of cylinder= 2πrh

= 2×22/7×7/2×14

=2×22×7

=308

Therefore, CSA of cylinder is 308sq.cm

HEMISPHERE

GIVEN:

Radius of hemisphere (r) = 7/2

CSA of hemisphere= 2πr²

=2×22/7×7/2

=2×11

=22

Therefore, CSA of one hemisphere is 22sq.cm

Adding CSA of cylinder and two hemisphere

308+2×22

=352sq cm

180° sector

Radius(r) = 7/2

area of 180°sector= 1/2πr²

=1/2×22/7×7/2×7/2

=1/2×11×7/2

=19.25

Therefore, area of 180°sector is 19.25sq.cm

Total area of shaded area = CSA of cylinder and hemispheres – area of 180°sector

=352–18.25

=332.75

Therefore area of shaded area is 332.75 sq cm

Hope it is right

Thanks


gowthamcrontecpausiq: u deserve it
mee30: But whole answer
mee30: Is wrong
mee30: Do a favor
mee30: Deleted
mee30: Delete my answer I'll again answer correct
gowthamcrontecpausiq: do it in comment section bro
mee30: Ok
mee30: Area of rectangle= lb =14×7 = 98 Area of two equal hemisphere= 1/2πr²= 1/2×22/7×7/2×7/2 =1/2×7/2 =19.25 as they are equal hemispheres hence total is 385 area of sector with diameter 14 =1/2πr² =1/2×22/7×14/2 =11 area of rectangle + area of semicircles = 98+385 = 483 . total area of shaded region=483–11 = 472 therefore total area of shaded region is 472 sq cm
gowthamcrontecpausiq: thanks a lot... (×_×)
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