if the weight of 5.6 litres of a gas at N.T.P is 11gm the gas
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22.4L of gas = 1mol
1L= 1/22.4 mol
5.6L = 1/4 mol
let molar mass of gas is M then
5.6L = M/4gm =11gm (given)
so M=11*4=44gm
so the gas is N2O
1L= 1/22.4 mol
5.6L = 1/4 mol
let molar mass of gas is M then
5.6L = M/4gm =11gm (given)
so M=11*4=44gm
so the gas is N2O
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