If the width of a rectangle is 2 metre less than its length and its perimeter is 32 metre then
the area of the rectangle is __
Answers
Answered by
0
Answer:
let the width of the rectangle be x
lenght=x+2
perimeter of a rectangle =2(l+b)
32 m= 2(x+x+2)
16= 2x+2
=>x= 14/2=7 m
so, l=9 m
and, b= 7 cm
NOW, AREA OF A RECTANGLE IS LENGTH * WIDTH
AREA= 9* 7
=63 m^2
HOPE IT HELPS
Answered by
0
Answer:
63m^2
Step-by-step explanation:
Let the length be x
According to question,b=x-2
perimeter =2 (l+b)
=>2(x+x-2)=32
=>4x-4=32
=>4x=36
=>x=36/4
=>x=9m
b=9-2=7m
AREA=l×b
=9×7m^2
=63m^2
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