Math, asked by generalnishant7, 1 year ago

If the width of a rectangle is 30 cm and the perimeter of the rectangle is 2.08 m then what is the ratio of the width of the rectangle to its length?

Answers

Answered by NKnav
0
perimeter = 2 ( l + b) = 208 cm
2( l + 30) = 208 cm


2l + 60 = 208 cm
2l = 148 cm
l = 74 cms


Hence l:b. = 30:74 = 15:37

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Answered by Anonymous
1

Answer:

The ratio of the width of the rectangle to its length is 15:37.

Step-by-step explanation:

Given :-

  • The width of a rectangle is 30 cm and the perimeter of the rectangle is 208 m.

To find :-

  • Ratio of the width of the rectangle to its length.

Solution :-

Let the length of the rectangle be x m.

Formula used :

{\boxed{\sf{Perimeter\:of\: rectangle=2(length+width)}}}

  • Width = 30 m

According to the question,

2(l+b) = 208

→ 2 (x + 30) = 208

→ x+30 = 208/2

→ x+30 = 104

→ x = 104-30

→ x = 74

  • Length of the rectangle = 74 m

Then,

Ratio of the width of the rectangle to its length,

= 30 : 74

= 15 : 37

__________________

Verification :-

  • Length of the rectangle = 74 m
  • Width of the rectangle = 30 m

Perimeter of the rectangle = 208

→ 2(74+30) = 208

→ 2×104 = 208

→ 208 = 208

Hence Verified !

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