If the x+1 is the zero of the polynomial px^3+2x^2+5x+4 then find p of cubic polynomial?
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Answer: x+1=0
x= -1
px^3+2x^2+5x+4 = 0
= p(-1)^3+2(-1)^2+5(-1)+4 = 0
= p(-1) + 2(1) + (-5) + 4 = 0
= -p + 2 - 5 + 4 = 0
= -p +1 = 0
= 1 = p
Therefore, p of this cubic polynomial is equal to 1.
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