If the young's modular of elasticity of a material is twice its modulus of rigidity, then the poisson's ratio of the material is
Answers
Answered by
13
the answer is zero.
Explanation: the relation between poisson's ratio, modulus of elasticity and modulus of rigidity is
E= 2G(1+Mu)
where, Mu- poisson's ratio.
E- modulus of elasticity.
G- Modulus of rigidity.
Now according to the question, E= 2G
=> 2G =2G(1+Mu)
=> 1 = 1+Mu
=> Mu = 0.
Explanation: the relation between poisson's ratio, modulus of elasticity and modulus of rigidity is
E= 2G(1+Mu)
where, Mu- poisson's ratio.
E- modulus of elasticity.
G- Modulus of rigidity.
Now according to the question, E= 2G
=> 2G =2G(1+Mu)
=> 1 = 1+Mu
=> Mu = 0.
Answered by
0
Answer:
zero
Explanation:
E=2G(1+Mu) where Mu is poissons
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