Question

If the zeores of the polynomial x^2+(a+b)x+b are 2 and -3 find the value of a and b

Answer 1

Answer:4+(a+b)2+b=0

Step-by-step explanation:4+2a+2b +b=0

4+2a+3b=0 and a=-3b-4/2when 0 is 2.

When zero is -3

9-3a-3b+b=0 9-3a-2b=0

-3a=2b-9 -27b-36/2=2b-6 Now you can easily solve this

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